x^2-8x-58=0

Solution for x^2-8x-58=0 equation:

x^2-8x-58=0

a = 1; b = -8; c = -58;
Δ = b2-4ac
Δ = -82-4·1·(-58)
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{74}}{2*1}=\frac{8-2\sqrt{74}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{74}}{2*1}=\frac{8+2\sqrt{74}}{2}
$